The first equation leads, as before, to
(28) t = C{T(V) - T(v)},
(29) x = C{S(V) - S(v)}.
The integration of (24) gives
| (30) | dy | = constant - gt = g(½T - t), |
| dt |
if T denotes the whole time of flight from O to the point B (fig. 1), where the trajectory cuts the line of sight; so that ½T is the time to the vertex A, where the shot is flying parallel to OB.
Integrating (27) again,
(31) y = g(½Tt - ½t2) = ½gt(T - t);
and denoting T - t by t′, and taking g = 32f/s2,
(32) y = 16tt′,