pn = anpn-1 + bnpn-2, qn = anqn-1 + bnqn-2 ;

and the first two partial quotients are given by

b1 = p1, a1 = q1, b1a2 = p2, a1a2 + b2 = q2.

If we form then the continued fraction in which p1, p2, p3, ..., pn are u1, u1 + u2, u1 + u2 + u3, ..., u1 + u2 + ..., un, and q1, q2, q3, ..., qn are all unity, we find the series u1 + u2 + ..., un equivalent to the continued fraction

u1 u2 ⁄ u1 u3 ⁄ u2 un ⁄ un-1
1 - 1 + u2 - 1 + u3 - ... - 1 + un
u1u2un-1

which we can transform into

u1 u2 u1u3 u2u4 un-2un ,
1 - u1 + u2 - u2 + u3 - u3 + u4 - ... - un-1 + un

a result given by Euler.

2. In this case the sum to n terms of the series is equal to the nth convergent of the fraction. There is, however, a different way in which a Series may be represented by a continued fraction. We may require to represent the infinite convergent power series a0 + a1x + a2x² + ... by an infinite continued fraction of the form

β0 β1x β2x β3x
1 - 1 - 1 - 1 - ...