x = 1+ 1( 1+ 1+ 1)
z − θ 3θ − φ θ − ψθ − χ

is at once reduced to the form y2 = 4x3 − g2x − g3 = 4(x − e1) (x − e2) (x − e3), say; and these equations enable us to express s and z rationally in terms of x and y. It is therefore sufficient to consider three elliptic integrals

u = ∫ dx,   J = ∫ xdx,   P = ∫ y + y0 dx.
y yx − x0 2y

Of these consider the first, putting

u = ∫ (∞)(x) dx,
y

where the limits involve not only a value for x, but a definite sign for the radical y. When x is very large, if we put x−1 = t2, y−1 = 2t3 (1 − ¼ g2t4 − ¼ g3t6)−1/2, we have

u = ∫ t0 (1 + 1⁄8 g2t4 + ... ) dt = t + 1⁄40 g2t5 + ...,

whereby a definite power series in u, valid for sufficiently small value of u, is found for t, and hence a definite power series for x, of the form

x = u−2 + 1⁄20 g2u2 + ...