F = − CR + K− Ra2,
M

(19)

N= − D=
( A+ a2 ) n2 + g (a − ρ)
M
,
L F
( C+ a2 ) R + K
M M

(20)

( A+ a2 ) n2 = (CR + K)[( C+ a2 ) R + K] − g (a − ρ).
M AM M

(21)

Thus with K = 0, and rolling with velocity V = Ra, stability requires

V2> a − ρ> ½ A a − ρ,
2g 2C/A (C/Ma2 + 1) C C/Ma2 + 1

(22)

or the body must have acquired velocity greater than attained by rolling down a plane through a vertical height ½ (a − ρ) A/C.