1 dp+ 4πρBy + hx + βy + fz = 0,
ρ dy

(12)

1 dp+ 4πρCz + gx + fy + γz = 0,
ρ dz

(13)

and integrating

pρ−1 + 2πρ (Ax2 + By2 + Cz2)
+ ½ (αx2 + βy2 + γz2 + 2fyz + 2gzx + 2hxy) = const.,

(14)

so that the surfaces of equal pressure are similar quadric surfaces, which, symmetry and dynamical considerations show, must be coaxial surfaces; and f, g, h vanish, as follows also by algebraical reduction; and

α = 4c2(c2 − a2)Ω22 − ( c2 − a2Ω2 − η ) 2
(c2 + a2)2 c2 + a2
4b2(a2 − b2)Ω32 − ( a2 − b2Ω3 − ζ ) 2,
(a2 + b2)2 a2 + b2