∫1/2π0 sin2n+1 x dx = ∫1/2π0 cos2n+1 x dx = 2·4 ... 2n, (n an integer).
3·5 ... (2n + 1)

(xi.)

dxcan be reduced by one of the substitutions
(1 + e cos x)n
cos φ = e + cos x,   cosh u = e + cos x,
1 + e cos x 1 + e cos x

of which the first or the second is to be employed according as e < or > 1.

50. New transcendents.Among the integrals of transcendental functions which lead to new transcendental functions we may notice

∫x0 dx,   or ∫log x−∞ ezdz,
log x z

called the “logarithmic integral,” and denoted by “Li x,” also the integrals

∫x0 sin xdx and ∫x∞ cos xdx,
x x

called the “sine integral” and the “cosine integral,” and denoted by “Si x” and “Ci x,” also the integral