whence

tan β Atan α.
C

(7)

Fig. 81.

Hence β ≷ α, and the circumstances are therefore those of the first or second case in fig. 78, according as A ≷ C. If ψ be the rate at which the plane HOJ revolves about OH, we have

ψ = sin αω = C cos αω,
sin β A cos β

(8)

by § 18 (3). Also if χ̇ be the rate at which J describes the polhode, we have ψ̇ sin (β − α) = χ̇ sin β, whence

χ̇ = sin (α − β)ω.
sin α

(9)