θ̈ − sin θ cos θψ̇2= − (g/l) sin θ,
sin2 θψ̇= h,

(23)

where h is a constant. The latter equation expresses that the angular momentum ml2 sin2 θψ̇ about the vertical OZ is constant. By elimination of ψ̇ we obtain

θ̈ − h2 cos2 θ / sin3 θ = − gsin θ.
l

(24)

If the particle describes a horizontal circle of angular radius α with constant angular velocity Ω, we have ω̇ = 0, h = Ω2 sin α, and therefore

Ω2 = gcos α,
l

(25)

as is otherwise evident from the elementary theory of uniform circular motion. To investigate the small oscillations about this state of steady motion we write θ = α + χ in (24) and neglect terms of the second order in χ. We find, after some reductions,

χ̈ + (1 + 3 cos2 α) Ω2χ = 0;