N. B. This rule is sufficiently exact for practical uses.
To find the diameter of the Shot, when the weight is given. Rule. Multiply the cube root of the weight in pounds by 1.923, and the product is the diameter in inches.
Example. What is the diameter of an iron shot of 52 pounds? The cube root of 52 is 3.732, which multiplied by 1.923 gives 7.177 inches, the diameter required.
Rule by logarithms.
| To ¹⁄₃d of the log. of 52 | 0.572001 |
| Add the constant log. | 0.283979 |
| And the sum is the log. of the diameter 7.177 | 0.855980 |
To find the diameter of a Shot, from the impression or cavity it makes by striking a brass gun, or other object. Rule. Divide the square of the radius of the cavity by the depth of it, and add the quotient to the depth; so will the sum be the diameter of the shot required.
Example. A shot having struck upon a brass gun, made a cavity of 1.49 inches deep, and 4.94 inches diameter; what was the size of the shot? The radius of the cavity is 2.47, and its square is 6.1009, which divided by the depth 1.49, the quotient is 4.1, to which adding 1.49, the sum 5.59 inches is the diameter required, answering to a 24 pounder.
Shot.—Rules for finding the number in any pile.
Triangular pile.
Multiply the base by the base + 1, this product by the base + 2, and divide by 6.