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Thus, Fig. 241, let the portion cut by the lines AB, S′ be the reading of the stadium; then
S′(cos a) = S.
The inclined distance is then equal to
(f/i)S′(cos a) + f + c
and the horizontal projection of that distance or
a = ((f/i)S′(cos a) + f + c)cos a;
or as f + c is small and the angle generally small also, f + c may be taken equal to (f + c) cos a. Then
a=(f/i)S′ cos2 a + f + c.