Then, because the angle B A C is half of B and B A C, it must be half of their equal E C B.
But E C B, being at the centre, is measured by B E; then half of it, or B A C, must be measured by half B E.
In like manner, it may be proved that the angle C A D is measured by half E D.
Then, because B A C is measured by half B E, and C A D by half E D, the whole angle B A D must be measured by half the whole arc B D.
SECOND CASE.
Suppose the angle were wholly on one side of the centre, as F A B.
Draw the diameter A E and the radius B C as before.
Prove that the angle B A E is measured by half the arc B E.
Draw another radius from C to F, and prove that F A E is measured by half the arc F E.
Then, because the angle F A E is measured by half the arc F E, and the angle B A E is measured by half the arc B E,