The 8 statements occurring in this problem are, respectively: 1 1 2 2 3 3 4 4. These are the values at which the V switches (the statement dial switches, Unit 2) from V₁ to V₈ are set. The 7 connectives occurring in this problem are, respectively: and, if-then, and, if-then, and, if-then, if-then. These are the values at which the k switches (the connective dial switches, Unit 4) from k₁ to k₇ are set.

A grouping (one of several possible groupings) that specifies the antecedent and consequent of each connective is the following:

1and1if-then2and2if-then3and3if-then4if-then4
| | | | | |
k kk
| | | |
k k
| |
k
| |
k

The grouping has here been expressed graphically with lines but may be expressed in the normal mathematical way with parentheses and brackets as follows:

{[ 1 and (1 if-then 2)] and [(2 if-then 3) and (3 if-then 4) ] } if-then 4.

So the values at which the antecedent and consequent dial switches are set are as shown in [Table 13].

Table 13

Connective Antecedent
Switch
Set at Consequent
Switch
Set at
kAVCk
kAVCV
kAkCk
kAVCV
kAkCk
kAVCV
kAkCV

In any problem, statements that are different are numbered one after another 1, 2, 3, 4 ···. A statement that is repeated bears always the same number. In nearly all cases that are interesting, there will be repetitions of the statements. If any statement appeared with a “not” in it, we would turn up the denial switch for that statement (Unit 2).

The different connectives available on the machine are “and,” “or,” “if ··· then,” “if and only if.” If a “not” affected the compound statement produced by any connective, we would turn up the denial switch for that connective (Unit 8).