Different methods of determining the thickness of an abutment have from time to time been given; several very correct rules have been arrived at, but difficult of application. The most simple rule is given by Hutton in the course of mathematics edited by Rutherford; it is as follows:—
Fig. 120.
Let A B, C D, fig. 120, be one half of the arch and A G F the abutment.
From the centre of gravity K of the arch, draw the vertical K L; then the weight of the arch in the direction K L will be to the horizontal thrust, as K L to L A. For the weight of the arch in the direction K L, the horizontal thrust L A, and the thrust K A will be as the three sides of the triangle K L, L A, K A; so that if m denotes the weight of the arch,
LA
KL × m,
will be its force in the direction L A, and
LA
KL × GA × m
its effect on the lever G A to overturn the wall, or cause it to revolve about the point F.
Again, the weight or area of the pier is as EF × FG, and therefore EF × FG × ½FG, or ½FG2 × EF, is its effect upon the lever ½FG, to resist an overthrow. Now that the abutment and the arch shall be in equilibrium these two effects must be equal to each other; whence we must have