Diameter two inches, surface 1466, length fourteen feet, we have,

N = 1466
14 × 0.167 × 3.1416 = 200.

375. Table 10. Giving the number and dimensions of tubes to obtain any given amount of surface.

L’gth.Diam. 1½Diam. 1¾Diam. 1⅞Diam. 2Diam. 2⅛Diam. 2¼Diam. 2⅜Diam. 2½L’gth.
83143363974194454715045238
334389422445473500535556
93524114474715075305665889
372435471497523559597621
1039245749652455658962865510
10½41148052154958461865968710½
1143150354557661264769072011
11½45152657060264067772175311½
1247154959562866770575278612
12½49057262065469573578381812½
1351059564568172376481485113
13½53061766970775079384588413½
1454964069573377882387691614
14½56966371975980685290794914½
1558968674478583488293898215
15½608708769811861911969101515½
166287317948378899411000104816
16½6487548198639179711031108116½
1766877784388994510001062111417

FORMULA.

13.5√a – 28,

where a is the percentage of admission.

Example.

What is the mean pressure, with an initial pressure of one hundred pounds, and sixty per cent. admission.

13.5√60 – 28 = (13.5 × 7.7) – 28 = 76
100 of 100, or 76 lbs.