or using the usual symbols
E = I × feet × 10.8 circular mils . . . . (3)
or expressed in words, formula (3) means that the volts lost or drop between the beginning and end of a circuit is equal to the current flowing through the circuit multiplied by the product of the conductors' length in feet multiplied by the resistance of one mil foot of wire, divided by the area of the conductor in circular mils.
LAMP TABLE FOR WEATHER PROOF WIRES
Showing the maximum number of 16 candle power 120 to 240 volt lamps in parallel that may be carried by various sizes of weather proof wire without violating the underwriters' rules.
| Wire size B. & S. gauge | Amperes. | 3.1.watt lamps. | 3.5.watt lamps. | 4.watt lamps. | ||||
|---|---|---|---|---|---|---|---|---|
| 110 V. | 220 V. | 110 V. | 220 V. | 220 V. | 230 V. | 240 V. | ||
| 0000 | 312 | 686 | 1372 | 612 | 1225 | 1072 | 1121 | 1170 |
| 000 | 262 | 576 | 1152 | 514 | 1029 | 900 | 941 | 982 |
| 00 | 220 | 484 | 968 | 432 | 864 | 756 | 790 | 825 |
| 0 | 185 | 407 | 814 | 363 | 726 | 636 | 665 | 693 |
| 1 | 156 | 343 | 686 | 306 | 612 | 536 | 560 | 585 |
| 2 | 131 | 288 | 576 | 257 | 514 | 450 | 470 | 491 |
| 3 | 220 | 242 | 484 | 216 | 432 | 378 | 395 | 412 |
| 4 | 92 | 202 | 404 | 180 | 361 | 316 | 330 | 345 |
| 5 | 77 | 169 | 338 | 151 | 302 | 264 | 276 | 288 |
| 6 | 65 | 143 | 286 | 127 | 255 | 223 | 233 | 243 |
| 8 | 46 | 101 | 202 | 90 | 180 | 158 | 165 | 172 |
| 10 | 32 | 70 | 140 | 62 | 125 | 110 | 115 | 120 |
| 12 | 23 | 50 | 101 | 45 | 90 | 79 | 82 | 86 |
| 14 | 16 | 35 | 70 | 31 | 62 | 55 | 57 | 60 |
Now, since the length of the circuit is given as the "run" or distance one way, that is, one half the total length of wire in the circuit, formula (3) must be multiplied by 2 to get the total drop, that is:
E = I × feet × 10.8 X 2 circular mills = I × feet × 21.6 circular mills . . . . (4)
Solving the last equation for the unknown quantity, the following equation is obtained for size of wire: