Foster's Complete Hoyle: An Encyclopedia of Games / Including all indoor games played to-day. With suggestions for good play, illustrative hands, and all official laws to date - R. F. Foster

Tricks bid by the player.	Number of tricks by which the player falls short of his declaration.
Tricks bid by the player.	1	2	3	4	5	6	7	8	9	10	11	12	13
Five	11	21	31	41	50
Six	15	24	35	45	55	66
Seven	19	29	40	50	60	72	82
Eight	23	34	46	56	67	78	89	110
Nine	33	44	57	68	82	92	103	115	127
Ten	44	56	70	82	94	107	119	132	145	157
Eleven	67	80	95	109	123	138	151	165	180	194	208
Twelve	113	130	148	165	182	200	217	234	252	270	286	304
Thirteen	177	198	222	241	262	284	305	326	348	369	390	412	433

We give the same table reduced to the American decimal system, in which form it is commonly found in the clubs. It may be remarked in passing that the table is very illogical and inconsistent, the payments bearing no relation to the probabilities of the events. Some of them provide for impossibilities, unless the player has miscalled the trump suit, and is held to it, but we have no authority to change them.

Tricks bid.	Number of tricks bidder is “put in for.”
Tricks bid.	1	2	3	4	5	6	7	8	9	10	11	12	13
Five	10	20	30	40	50
Six	15	25	35	45	55	65
Seven	20	30	40	50	60	70	80
Eight	25	35	45	55	70	85	100	115
Nine	35	45	55	65	80	95	110	125	140
Ten	45	55	70	80	95	110	125	140	155	170
Eleven	70	80	95	110	125	140	155	170	185	200	220
Twelve	120	130	145	160	180	200	220	240	260	280	300	320
Thirteen	180	200	220	240	260	280	300	320	340	360	390	420	450

If a misère is bid, the caller wins from, or loses to each adversary according to the following table, there being no over-tricks:—

Little Misère,	20 white counters.
Grand Misère,	40 white counters.
Little Spread,	80 white counters.
Grand Spread,	160 white counters.

It may be observed that each of these is twice the amount of the next lower.

When misère partout is played, the person winning the largest number of tricks is the only loser, and he must pay each of the other players the difference between the number of his tricks and theirs in red counters. The number of red counters lost will always be found to be three times the number of tricks taken, minus the number of tricks not taken. For instance: A wins 4 tricks, three times which is 12; from which he deducts 9, the number he did not take, and finds his loss to be 3 red counters. Again; A wins 7 tricks; three times which is 21; minus 6 tricks not taken, a net loss of 15. No matter in what proportion the other tricks may be divided between the three other players, this total payment will always be found correct. For instance: A wins 6 tricks; Y 2; B 5; and Z none. A loses 6 x 3 = 18-7 = 11, of which he gives 4 to Y; 1 to B; and 6 to Z.

If two players tie for the greatest number of tricks taken, they calculate their losses in the same manner; but each pays only half the total. For instance: A and Y each take 5 tricks; B taking 1, and Z 2. The 7 red counters lost by A and Y being divided, shows a loss of 35 white counters for each of them. If three players take four tricks apiece, they each pay the fourth man a red counter.