If the duplicates are of two different cards, the combination is still worth 12, because four different fifteens can be formed by combining each Nine with each Six separately, and there are two single pairs.
The same is true of any combinations of two-card fifteens in which all five cards are of value; they are both of the same pegging value, 20 points. If there are three duplicates of one card in the original fifteen, the four separate fifteens will be worth 8, and the double pair royal 12. If there are two duplicates of one card, and one of the other, six separate fifteens can be formed by combining each Nine with each Six, pegging 12; and the pair royal of one card with the single pair of the other will add 8 more.
Three-card Fifteens may be formed in fifteen different ways, ranging from 10 4 A, to 5 5 5. If you hold any of these combinations, and have a fourth card which is a duplicate of any of the three forming the fifteen, the value of the combination will depend on how many cards you can replace with the duplicate card.
If you have an extra tenth card, you can replace the other tenth card once only, and the total value of the combination is therefore 6 points, which is expressed by the formula; “Fifteen-two, fifteen-four, and a pair.”
If your combination was 9 3 3, and you had another 9, the same thing would be true; but if your duplicate is a Three, there are two cards which can be replaced, and the combination is therefore worth 12; 6 for the three fifteens, and 6 more for the pair royal.
