If your combination is one in which all three cards can be replaced with the duplicate, making three extra fifteens, it must be worth 20 altogether; 8 for the four fifteens, and 12 for the double pair royal.
If you have two duplicates of any one card in the original combination, there are only two extra fifteens, and the combination will be worth 12; 6 for the three fifteens, and 6 more for the pair royal.
If you have duplicates of two different cards you can form four fifteens; because you can replace the Seven first, and then the Six, and then put the first Seven back again with the new Six. This will make the combination of the same value as if you had three duplicates of one card, 12 points; 8 for the four fifteens, and 4 for the two single pairs.
Combinations. The beginner’s greatest difficulty is in counting hands which contain all three varieties of counts; pairs, sequences, and fifteens. But if he is familiar with the values of the various combinations taken separately, he will have no difficulty in computing them when they are found together. Some regular order should be observed in going over the hands, so that nothing shall be forgotten. The majority of players begin with the fifteens, as they are more liable to be overlooked, and then reckon the value of the runs and pairs together.
Take the following examples:—
| No. 1. | |
| No. 2. | |
| No. 3. | |
| No. 4. |
No. 1 contains a fifteen in addition to the three runs of three and the pair royal, and is therefore worth 17 altogether. Nos. 2 and 3 each contain three fifteens; but No. 2 is worth 21 points on account of the three runs of three and the pair royal, while No. 3 is worth only 16; a double run of four and a single pair. No. 4 contains four fifteens in addition to the four runs of three and two single pairs, and is therefore worth 24 points.