And lastly, with that difference, find by the 3d Table, the Height at the Standard-Heat, corresponding to the remaining Decimals above the upper Barometer.

421. (1st.) From the lower Barom. viz.30.082
Subtract the upper29.9865
———
Remaining Decimals above the upper.0955

2d. Find, by the 2d Table, the Height corresponding to the Inches, and nearest Tenth above and below the Point at which the Quicksilver rests in the lower Barometer.

The Inches and nearest Tenth is

above 30 Inches, correspond. to Feet1681.7
and below 30.1, corresponding to1595.0
———
86.7

which is the difference of .1 below 30.1.

Lastly. Find, by the 3d Table, with the difference, viz. 86 Feet, on the remaining Decimals, for the Height, in Feet, corresponding to the Standard-Heat.

viz. .09 77 = 77. Feet.
.005 43 = 4.3
.0005 43 = .43
———
Answer, Height in Feet 81.73

corresponding to .0955 above Inches 29.9865 Tenths of an Inch, of Quicksilver in the upper Barometer thus brought to the Standard-Heat.

422. Prepare for Expansion of Air from Excess above Standard-Heat, on the same Number of Feet: