then
| arc CA' | = | arc BB' |
| r | r' |
or, omitting the word "arc" and clearing of fractions,
r'(CA') = r(BB').
But now
CA' = BA' - BC,
while
BA' = Z and BC = p;
therefore
CA' = Z-p.
then
| arc CA' | = | arc BB' |
| r | r' |
or, omitting the word "arc" and clearing of fractions,
r'(CA') = r(BB').
But now
CA' = BA' - BC,
while
BA' = Z and BC = p;
therefore
CA' = Z-p.