it appears that this is
| = x | a, | b, | c | + y | b, | b, | c | + z | c, | b, | c | - | d, | b, | c | ; | ||||||||
| a′, | b′, | c′ | b′, | b′, | c′ | c′, | b′, | c′ | d′, | b′, | c′ | |||||||||||||
| a″, | b″, | c″ | b″, | b″, | c″ | c″, | b″, | c″ | d″, | b″, | c″ |
viz. the second and third terms each vanishing, it is
| = x | a, | b, | c | - | d, | b, | c | . | ||||
| a′, | b′, | c′ | d′, | b′, | c′ | |||||||
| a″, | b″, | c″ | d″, | b″, | c″ |
But if the linear equations hold good, then the first column of the original determinant is = 0, and therefore the determinant itself is = 0; that is, the linear equations give
| x | a, | b, | c | - | d, | b, | c | = 0; | ||||
| a′, | b′, | c′ | d′, | b′, | c′ | |||||||
| a″, | b″, | c″ | d″, | b″, | c″ |
which is the result obtained above.
We might in a similar way find the values of y and z, but there is a more symmetrical process. Join to the original equations the new equation
αx + βy + γz = δ;
a like process shows that, the equations being satisfied, we have