C = prJ0(z) zdz = { p²R² p4R4+ p6R6− ...}= πR² · 2J1(pR)as before.
0 22²·4² 2²·4²·6² pR

In these expressions we are to replace p by kξ/ƒ, or rather, since the diffraction pattern is symmetrical, by kr/ƒ, where r is the distance of any point in the focal plane from the centre of the system.

The roots of J0(z) after the first may be found from

z = i − .25 + .050561 .053041+ .262051     (13),
π 4i − 1(4i − 1)³ (4i − 1)5

and those of J1(z) from

z = i + .25 − .151982+ .015399 .245835     (14),
π 4i + 1(4i + 1)³ (4i + 1)5

formulae derived by Stokes (Camb. Trans., 1850, vol. ix.) from the descending series.[1] The following table gives the actual values:—

iz/π for J0(z) = 0z/π for J1(z) = 0
176551 2197
21 75712 2330
32 75463 2383
43 75344 2411
54 75275 2428
65 75226 2439
76 75197 2448
87 75168 2454
98 75149 2459
109 751310 2463

In both cases the image of a mathematical point is thus a symmetrical ring system. The greatest brightness is at the centre, where

dC = 2πρ dρ, C = π R².